Base | Representation |
---|---|
bin | 11010001101010101000000… |
… | …000111111001010101101001 |
3 | 120010010020101220210112121120 |
4 | 122031111000013321111221 |
5 | 110102000422430300231 |
6 | 1045052021214525453 |
7 | 33164425645656144 |
oct | 3215250007712551 |
9 | 503106356715546 |
10 | 115265113134441 |
11 | 337aa729455556 |
12 | 10b17199206889 |
13 | 4c415b85325ba |
14 | 2066c0b36d05b |
15 | d4d49b95dd96 |
hex | 68d5401f9569 |
115265113134441 has 16 divisors (see below), whose sum is σ = 154006080146304. Its totient is φ = 76683784990464.
The previous prime is 115265113134439. The next prime is 115265113134491. The reversal of 115265113134441 is 144431311562511.
It is not a de Polignac number, because 115265113134441 - 21 = 115265113134439 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 115265113134393 and 115265113134402.
It is not an unprimeable number, because it can be changed into a prime (115265113134491) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61569105 + ... + 63413601.
It is an arithmetic number, because the mean of its divisors is an integer number (9625380009144).
Almost surely, 2115265113134441 is an apocalyptic number.
It is an amenable number.
115265113134441 is a deficient number, since it is larger than the sum of its proper divisors (38740967011863).
115265113134441 is a wasteful number, since it uses less digits than its factorization.
115265113134441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1887760.
The product of its digits is 172800, while the sum is 42.
Adding to 115265113134441 its reverse (144431311562511), we get a palindrome (259696424696952).
The spelling of 115265113134441 in words is "one hundred fifteen trillion, two hundred sixty-five billion, one hundred thirteen million, one hundred thirty-four thousand, four hundred forty-one".
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