Base | Representation |
---|---|
bin | 11010001101010101000000… |
… | …000111111001010101000010 |
3 | 120010010020101220210112120010 |
4 | 122031111000013321111002 |
5 | 110102000422430300102 |
6 | 1045052021214525350 |
7 | 33164425645656060 |
oct | 3215250007712502 |
9 | 503106356715503 |
10 | 115265113134402 |
11 | 337aa729455520 |
12 | 10b17199206856 |
13 | 4c415b853258a |
14 | 2066c0b36d030 |
15 | d4d49b95dd6c |
hex | 68d5401f9542 |
115265113134402 has 64 divisors (see below), whose sum is σ = 287461178717184. Its totient is φ = 29934108066240.
The previous prime is 115265113134377. The next prime is 115265113134427. The reversal of 115265113134402 is 204431311562511.
It is an interprime number because it is at equal distance from previous prime (115265113134377) and next prime (115265113134427).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17506648 + ... + 23173539.
It is an arithmetic number, because the mean of its divisors is an integer number (4491580917456).
Almost surely, 2115265113134402 is an apocalyptic number.
115265113134402 is an abundant number, since it is smaller than the sum of its proper divisors (172196065582782).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115265113134402 is a wasteful number, since it uses less digits than its factorization.
115265113134402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40686343.
The product of its (nonzero) digits is 86400, while the sum is 39.
Adding to 115265113134402 its reverse (204431311562511), we get a palindrome (319696424696913).
The spelling of 115265113134402 in words is "one hundred fifteen trillion, two hundred sixty-five billion, one hundred thirteen million, one hundred thirty-four thousand, four hundred two".
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