Base | Representation |
---|---|
bin | 10000110001100101011… |
… | …000010111100010010101 |
3 | 11002012110021111020000020 |
4 | 100301211120113202111 |
5 | 122341314020401010 |
6 | 2241322250335353 |
7 | 146166162236421 |
oct | 20614530274225 |
9 | 4065407436006 |
10 | 1152752122005 |
11 | 404974580040 |
12 | 1674b242a559 |
13 | 8491ca80953 |
14 | 3db17517b81 |
15 | 1eebbc74470 |
hex | 10c65617895 |
1152752122005 has 16 divisors (see below), whose sum is σ = 2012076431424. Its totient is φ = 558910119680.
The previous prime is 1152752122003. The next prime is 1152752122033. The reversal of 1152752122005 is 5002212572511.
It is not a de Polignac number, because 1152752122005 - 21 = 1152752122003 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1152752122003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3493188084 + ... + 3493188413.
It is an arithmetic number, because the mean of its divisors is an integer number (125754776964).
Almost surely, 21152752122005 is an apocalyptic number.
1152752122005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1152752122005 is a deficient number, since it is larger than the sum of its proper divisors (859324309419).
1152752122005 is a wasteful number, since it uses less digits than its factorization.
1152752122005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6986376516.
The product of its (nonzero) digits is 14000, while the sum is 33.
Adding to 1152752122005 its reverse (5002212572511), we get a palindrome (6154964694516).
The spelling of 1152752122005 in words is "one trillion, one hundred fifty-two billion, seven hundred fifty-two million, one hundred twenty-two thousand, five".
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