Base | Representation |
---|---|
bin | 10000110001111100001… |
… | …011101100010010100001 |
3 | 11002020102221022221012120 |
4 | 100301330023230102201 |
5 | 122343104434100410 |
6 | 2241424234014453 |
7 | 146211516004530 |
oct | 20617413542241 |
9 | 4066387287176 |
10 | 1153134675105 |
11 | 405050509926 |
12 | 16759a577429 |
13 | 849810c3c2a |
14 | 3db5225a317 |
15 | 1eee063d570 |
hex | 10c7c2ec4a1 |
1153134675105 has 32 divisors (see below), whose sum is σ = 2109114547200. Its totient is φ = 527015923392.
The previous prime is 1153134675079. The next prime is 1153134675137. The reversal of 1153134675105 is 5015764313511.
It is not a de Polignac number, because 1153134675105 - 211 = 1153134673057 is a prime.
It is a super-2 number, since 2×11531346751052 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 944295 + ... + 1788284.
It is an arithmetic number, because the mean of its divisors is an integer number (65909829600).
Almost surely, 21153134675105 is an apocalyptic number.
1153134675105 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1153134675105 is a deficient number, since it is larger than the sum of its proper divisors (955979872095).
1153134675105 is a wasteful number, since it uses less digits than its factorization.
1153134675105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2736613.
The product of its (nonzero) digits is 189000, while the sum is 42.
Adding to 1153134675105 its reverse (5015764313511), we get a palindrome (6168898988616).
The spelling of 1153134675105 in words is "one trillion, one hundred fifty-three billion, one hundred thirty-four million, six hundred seventy-five thousand, one hundred five".
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