115313540011 has 4 divisors (see below), whose sum is σ = 115322180112. Its totient is φ = 115304899912.

The previous prime is 115313539967. The next prime is 115313540029. The reversal of 115313540011 is 110045313511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110045313511 = 7 ⋅15720759073.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115313540011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115313541011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4300000 + ... + 4326733.

It is an arithmetic number, because the mean of its divisors is an integer number (28830545028).

Almost surely, 2^115313540011 is an apocalyptic number.

115313540011 is a deficient number, since it is larger than the sum of its proper divisors (8640101).

115313540011 is an equidigital number, since it uses as much as digits as its factorization.

115313540011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8640100.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 115313540011 its reverse (110045313511), we get a palindrome (225358853522).

The spelling of 115313540011 in words is "one hundred fifteen billion, three hundred thirteen million, five hundred forty thousand, eleven".