115314010513441 has 4 divisors (see below), whose sum is σ = 115524822233392. Its totient is φ = 115103198793492.

The previous prime is 115314010513411. The next prime is 115314010513447. The reversal of 115314010513441 is 144315010413511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115314010513441 - 2¹⁹ = 115314009989153 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115314010513397 and 115314010513406.

It is not an unprimeable number, because it can be changed into a prime (115314010513447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105405859155 + ... + 105405860248.

It is an arithmetic number, because the mean of its divisors is an integer number (28881205558348).

Almost surely, 2^{115314010513441} is an apocalyptic number.

It is an amenable number.

115314010513441 is a deficient number, since it is larger than the sum of its proper divisors (210811719951).

115314010513441 is an equidigital number, since it uses as much as digits as its factorization.

115314010513441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 210811719950.

The product of its (nonzero) digits is 14400, while the sum is 34.

Adding to 115314010513441 its reverse (144315010413511), we get a palindrome (259629020926952).

The spelling of 115314010513441 in words is "one hundred fifteen trillion, three hundred fourteen billion, ten million, five hundred thirteen thousand, four hundred forty-one".