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115322113143 = 3212813568127
BaseRepresentation
bin110101101100110111…
…0111100110001110111
3102000122222220100002200
41223121232330301313
53342134430110033
6124551145035543
711221534534206
oct1533156746167
9360588810080
10115322113143
11449a9365526
121a425185bb3
13ab4acc9793
14581dd7323d
152eee47a013
hex1ad9bbcc77

115322113143 has 6 divisors (see below), whose sum is σ = 166576385664. Its totient is φ = 76881408756.

The previous prime is 115322113103. The next prime is 115322113169. The reversal of 115322113143 is 341311223511.

115322113143 is a `hidden beast` number, since 1 + 1 + 532 + 2 + 113 + 14 + 3 = 666.

It is not a de Polignac number, because 115322113143 - 210 = 115322112119 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115322113103) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6406784055 + ... + 6406784072.

It is an arithmetic number, because the mean of its divisors is an integer number (27762730944).

Almost surely, 2115322113143 is an apocalyptic number.

115322113143 is a deficient number, since it is larger than the sum of its proper divisors (51254272521).

115322113143 is a wasteful number, since it uses less digits than its factorization.

115322113143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12813568133 (or 12813568130 counting only the distinct ones).

The product of its digits is 2160, while the sum is 27.

Adding to 115322113143 its reverse (341311223511), we get a palindrome (456633336654).

The spelling of 115322113143 in words is "one hundred fifteen billion, three hundred twenty-two million, one hundred thirteen thousand, one hundred forty-three".

Divisors: 1 3 9 12813568127 38440704381 115322113143