11532251001441 has 4 divisors (see below), whose sum is σ = 15376334668592. Its totient is φ = 7688167334292.

The previous prime is 11532251001421. The next prime is 11532251001443. The reversal of 11532251001441 is 14410015223511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11532251001441 - 2¹¹ = 11532250999393 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11532251001399 and 11532251001408.

It is not an unprimeable number, because it can be changed into a prime (11532251001443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1922041833571 + ... + 1922041833576.

It is an arithmetic number, because the mean of its divisors is an integer number (3844083667148).

Almost surely, 2^{11532251001441} is an apocalyptic number.

It is an amenable number.

11532251001441 is a deficient number, since it is larger than the sum of its proper divisors (3844083667151).

11532251001441 is an equidigital number, since it uses as much as digits as its factorization.

11532251001441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3844083667150.

The product of its (nonzero) digits is 4800, while the sum is 30.

Adding to 11532251001441 its reverse (14410015223511), we get a palindrome (25942266224952).

The spelling of 11532251001441 in words is "eleven trillion, five hundred thirty-two billion, two hundred fifty-one million, one thousand, four hundred forty-one".