115331254240053 has 4 divisors (see below), whose sum is σ = 153775005653408. Its totient is φ = 76887502826700.

The previous prime is 115331254240021. The next prime is 115331254240073. The reversal of 115331254240053 is 350042452133511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 115331254240053 - 2⁵ = 115331254240021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115331254239993 and 115331254240020.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115331254240073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19221875706673 + ... + 19221875706678.

It is an arithmetic number, because the mean of its divisors is an integer number (38443751413352).

Almost surely, 2^{115331254240053} is an apocalyptic number.

It is an amenable number.

115331254240053 is a deficient number, since it is larger than the sum of its proper divisors (38443751413355).

115331254240053 is an equidigital number, since it uses as much as digits as its factorization.

115331254240053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38443751413354.

The product of its (nonzero) digits is 216000, while the sum is 39.

The spelling of 115331254240053 in words is "one hundred fifteen trillion, three hundred thirty-one billion, two hundred fifty-four million, two hundred forty thousand, fifty-three".