11533125542413 has 4 divisors (see below), whose sum is σ = 11593508398848. Its totient is φ = 11472742685980.

The previous prime is 11533125542381. The next prime is 11533125542429. The reversal of 11533125542413 is 31424552133511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11533125542413 - 2⁵ = 11533125542381 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11533125542473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30191427931 + ... + 30191428312.

It is an arithmetic number, because the mean of its divisors is an integer number (2898377099712).

Almost surely, 2^{11533125542413} is an apocalyptic number.

It is an amenable number.

11533125542413 is a deficient number, since it is larger than the sum of its proper divisors (60382856435).

11533125542413 is an equidigital number, since it uses as much as digits as its factorization.

11533125542413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60382856434.

The product of its digits is 216000, while the sum is 40.

Adding to 11533125542413 its reverse (31424552133511), we get a palindrome (42957677675924).

The spelling of 11533125542413 in words is "eleven trillion, five hundred thirty-three billion, one hundred twenty-five million, five hundred forty-two thousand, four hundred thirteen".