Base | Representation |
---|---|
bin | 10000110010000111111… |
… | …101101110010111110111 |
3 | 11002020221201021100202120 |
4 | 100302013331232113313 |
5 | 122344011034341330 |
6 | 2241500014411023 |
7 | 146216436065616 |
oct | 20620775562767 |
9 | 4066851240676 |
10 | 1153332340215 |
11 | 405142047620 |
12 | 167634800a73 |
13 | 849b3041533 |
14 | 3db705d187d |
15 | 20002b85c10 |
hex | 10c87f6e5f7 |
1153332340215 has 16 divisors (see below), whose sum is σ = 2013089175936. Its totient is φ = 559191437600.
The previous prime is 1153332340189. The next prime is 1153332340217. The reversal of 1153332340215 is 5120432333511.
It is not a de Polignac number, because 1153332340215 - 215 = 1153332307447 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1153332340217) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3494946321 + ... + 3494946650.
It is an arithmetic number, because the mean of its divisors is an integer number (125818073496).
Almost surely, 21153332340215 is an apocalyptic number.
1153332340215 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1153332340215 is a deficient number, since it is larger than the sum of its proper divisors (859756835721).
1153332340215 is a wasteful number, since it uses less digits than its factorization.
1153332340215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6989892990.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 1153332340215 its reverse (5120432333511), we get a palindrome (6273764673726).
The spelling of 1153332340215 in words is "one trillion, one hundred fifty-three billion, three hundred thirty-two million, three hundred forty thousand, two hundred fifteen".
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