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115340215451 = 6710316713551
BaseRepresentation
bin110101101101011010…
…0000000010010011011
3102000201020222000210112
41223122310000102123
53342204043343301
6124553033034535
711222144440466
oct1533264002233
9360636860715
10115340215451
1144a085aa00a
121a42b255a4b
13ab519971c6
1458225262dd
153000d539bb
hex1adad0049b

115340215451 has 8 divisors (see below), whose sum is σ = 118198239744. Its totient is φ = 112515618600.

The previous prime is 115340215381. The next prime is 115340215457. The reversal of 115340215451 is 154512043511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 115340215451 - 210 = 115340214427 is a prime.

It is not an unprimeable number, because it can be changed into a prime (115340215457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8349875 + ... + 8363676.

It is an arithmetic number, because the mean of its divisors is an integer number (14774779968).

Almost surely, 2115340215451 is an apocalyptic number.

115340215451 is a deficient number, since it is larger than the sum of its proper divisors (2858024293).

115340215451 is a wasteful number, since it uses less digits than its factorization.

115340215451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16713721.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 115340215451 its reverse (154512043511), we get a palindrome (269852258962).

The spelling of 115340215451 in words is "one hundred fifteen billion, three hundred forty million, two hundred fifteen thousand, four hundred fifty-one".

Divisors: 1 67 103 6901 16713551 1119807917 1721495753 115340215451