Base | Representation |
---|---|
bin | 1010011111011000000001… |
… | …0101110111001010000001 |
3 | 1111211122122002001121221102 |
4 | 2213312000111313022001 |
5 | 3002433404420414403 |
6 | 40310413322104145 |
7 | 2300212515541400 |
oct | 247660025671201 |
9 | 44748562047842 |
10 | 11534140404353 |
11 | 3747668622516 |
12 | 136348834b055 |
13 | 658884677a08 |
14 | 2bc380a65637 |
15 | 150069672b88 |
hex | a7d80577281 |
11534140404353 has 6 divisors (see below), whose sum is σ = 13417265368386. Its totient is φ = 9886406060832.
The previous prime is 11534140404349. The next prime is 11534140404359. The reversal of 11534140404353 is 35340404143511.
It can be written as a sum of positive squares in only one way, i.e., 7790255956609 + 3743884447744 = 2791103^2 + 1934912^2 .
It is not a de Polignac number, because 11534140404353 - 22 = 11534140404349 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11534140404359) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 117695310200 + ... + 117695310297.
It is an arithmetic number, because the mean of its divisors is an integer number (2236210894731).
Almost surely, 211534140404353 is an apocalyptic number.
It is an amenable number.
11534140404353 is a deficient number, since it is larger than the sum of its proper divisors (1883124964033).
11534140404353 is an equidigital number, since it uses as much as digits as its factorization.
11534140404353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 235390620511 (or 235390620504 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 11534140404353 its reverse (35340404143511), we get a palindrome (46874544547864).
The spelling of 11534140404353 in words is "eleven trillion, five hundred thirty-four billion, one hundred forty million, four hundred four thousand, three hundred fifty-three".
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