Base | Representation |
---|---|
bin | 10101011110111111… |
… | …11010001001101001 |
3 | 1002202211211202120021 |
4 | 22233133322021221 |
5 | 142110240441131 |
6 | 5144312200441 |
7 | 555555014620 |
oct | 125737721151 |
9 | 32684752507 |
10 | 11534312041 |
11 | 498990039a |
12 | 229a999121 |
13 | 111a834315 |
14 | 7b5c386b7 |
15 | 477933e11 |
hex | 2af7fa269 |
11534312041 has 4 divisors (see below), whose sum is σ = 13182070912. Its totient is φ = 9886553172.
The previous prime is 11534312017. The next prime is 11534312051. The reversal of 11534312041 is 14021343511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11534312041 - 27 = 11534311913 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11534311997 and 11534312015.
It is not an unprimeable number, because it can be changed into a prime (11534312051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 823879425 + ... + 823879438.
It is an arithmetic number, because the mean of its divisors is an integer number (3295517728).
Almost surely, 211534312041 is an apocalyptic number.
It is an amenable number.
11534312041 is a deficient number, since it is larger than the sum of its proper divisors (1647758871).
11534312041 is an equidigital number, since it uses as much as digits as its factorization.
11534312041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1647758870.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 11534312041 its reverse (14021343511), we get a palindrome (25555655552).
The spelling of 11534312041 in words is "eleven billion, five hundred thirty-four million, three hundred twelve thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •