Base | Representation |
---|---|
bin | 10101011111000000… |
… | …00001010011100001 |
3 | 1002202211220020202121 |
4 | 22233200001103201 |
5 | 142110242410340 |
6 | 5144312544241 |
7 | 555555166222 |
oct | 125740012341 |
9 | 32684806677 |
10 | 11534341345 |
11 | 498992040a |
12 | 229a9b2081 |
13 | 111a844767 |
14 | 7b5c45249 |
15 | 47793c94a |
hex | 2af8014e1 |
11534341345 has 4 divisors (see below), whose sum is σ = 13841209620. Its totient is φ = 9227473072.
The previous prime is 11534341333. The next prime is 11534341367. The reversal of 11534341345 is 54314343511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6566347089 + 4967994256 = 81033^2 + 70484^2 .
It is a cyclic number.
It is not a de Polignac number, because 11534341345 - 29 = 11534340833 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11534341345.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1153434130 + ... + 1153434139.
It is an arithmetic number, because the mean of its divisors is an integer number (3460302405).
Almost surely, 211534341345 is an apocalyptic number.
It is an amenable number.
11534341345 is a deficient number, since it is larger than the sum of its proper divisors (2306868275).
11534341345 is an equidigital number, since it uses as much as digits as its factorization.
11534341345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2306868274.
The product of its digits is 43200, while the sum is 34.
Adding to 11534341345 its reverse (54314343511), we get a palindrome (65848684856).
The spelling of 11534341345 in words is "eleven billion, five hundred thirty-four million, three hundred forty-one thousand, three hundred forty-five".
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