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11534421341 = 17678495373
BaseRepresentation
bin10101011111000000…
…10100110101011101
31002202212001022111102
422233200110311131
5142110302440331
65144314402445
7555555651362
oct125740246535
932685038442
1011534421341
114989975523
12229aa30425
13111a871cb1
147b5c66469
154779564cb
hex2af814d5d

11534421341 has 4 divisors (see below), whose sum is σ = 12212916732. Its totient is φ = 10855925952.

The previous prime is 11534421289. The next prime is 11534421373. The reversal of 11534421341 is 14312443511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14312443511 = 75491895939.

It can be written as a sum of positive squares in 2 ways, for example, as 4897060441 + 6637360900 = 69979^2 + 81470^2 .

It is a cyclic number.

It is not a de Polignac number, because 11534421341 - 214 = 11534404957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11534421541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 339247670 + ... + 339247703.

It is an arithmetic number, because the mean of its divisors is an integer number (3053229183).

Almost surely, 211534421341 is an apocalyptic number.

It is an amenable number.

11534421341 is a deficient number, since it is larger than the sum of its proper divisors (678495391).

11534421341 is an equidigital number, since it uses as much as digits as its factorization.

11534421341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 678495390.

The product of its digits is 5760, while the sum is 29.

Adding to 11534421341 its reverse (14312443511), we get a palindrome (25846864852).

The spelling of 11534421341 in words is "eleven billion, five hundred thirty-four million, four hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 17 678495373 11534421341