115400121 has 4 divisors (see below), whose sum is σ = 153866832. Its totient is φ = 76933412.

The previous prime is 115400113. The next prime is 115400143. The reversal of 115400121 is 121004511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121004511 = 3 ⋅40334837.

It is a cyclic number.

It is not a de Polignac number, because 115400121 - 2³ = 115400113 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 115400121.

It is not an unprimeable number, because it can be changed into a prime (115400161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19233351 + ... + 19233356.

It is an arithmetic number, because the mean of its divisors is an integer number (38466708).

Almost surely, 2^115400121 is an apocalyptic number.

It is an amenable number.

115400121 is a deficient number, since it is larger than the sum of its proper divisors (38466711).

115400121 is an equidigital number, since it uses as much as digits as its factorization.

115400121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38466710.

The product of its (nonzero) digits is 40, while the sum is 15.

The square root of 115400121 is about 10742.4448334632. Note that the first 3 decimals coincide. The cubic root of 115400121 is about 486.8577504362.

Adding to 115400121 its reverse (121004511), we get a palindrome (236404632).

The spelling of 115400121 in words is "one hundred fifteen million, four hundred thousand, one hundred twenty-one".