Base | Representation |
---|---|
bin | 11010001111010010111010… |
… | …101110010100011000010011 |
3 | 120010121011101022002210122201 |
4 | 122033102322232110120103 |
5 | 110111204320341410303 |
6 | 1045234101122544031 |
7 | 33210253234325302 |
oct | 3217227256243023 |
9 | 503534338083581 |
10 | 115400314013203 |
11 | 33851aa886489a |
12 | 10b3942b808017 |
13 | 4c51283a69c8b |
14 | 206d59546a439 |
15 | d51c611a881d |
hex | 68f4bab94613 |
115400314013203 has 16 divisors (see below), whose sum is σ = 123812398069920. Its totient is φ = 107242016587776.
The previous prime is 115400314013183. The next prime is 115400314013239. The reversal of 115400314013203 is 302310413004511.
It is a cyclic number.
It is not a de Polignac number, because 115400314013203 - 221 = 115400311916051 is a prime.
It is not an unprimeable number, because it can be changed into a prime (115400314013273) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 276851350 + ... + 277267867.
It is an arithmetic number, because the mean of its divisors is an integer number (7738274879370).
Almost surely, 2115400314013203 is an apocalyptic number.
115400314013203 is a deficient number, since it is larger than the sum of its proper divisors (8412084056717).
115400314013203 is a wasteful number, since it uses less digits than its factorization.
115400314013203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 554119446.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 115400314013203 its reverse (302310413004511), we get a palindrome (417710727017714).
The spelling of 115400314013203 in words is "one hundred fifteen trillion, four hundred billion, three hundred fourteen million, thirteen thousand, two hundred three".
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