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115400314013203 = 1997113554119217
BaseRepresentation
bin11010001111010010111010…
…101110010100011000010011
3120010121011101022002210122201
4122033102322232110120103
5110111204320341410303
61045234101122544031
733210253234325302
oct3217227256243023
9503534338083581
10115400314013203
1133851aa886489a
1210b3942b808017
134c51283a69c8b
14206d59546a439
15d51c611a881d
hex68f4bab94613

115400314013203 has 16 divisors (see below), whose sum is σ = 123812398069920. Its totient is φ = 107242016587776.

The previous prime is 115400314013183. The next prime is 115400314013239. The reversal of 115400314013203 is 302310413004511.

It is a cyclic number.

It is not a de Polignac number, because 115400314013203 - 221 = 115400311916051 is a prime.

It is not an unprimeable number, because it can be changed into a prime (115400314013273) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 276851350 + ... + 277267867.

It is an arithmetic number, because the mean of its divisors is an integer number (7738274879370).

Almost surely, 2115400314013203 is an apocalyptic number.

115400314013203 is a deficient number, since it is larger than the sum of its proper divisors (8412084056717).

115400314013203 is a wasteful number, since it uses less digits than its factorization.

115400314013203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 554119446.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 115400314013203 its reverse (302310413004511), we get a palindrome (417710727017714).

The spelling of 115400314013203 in words is "one hundred fifteen trillion, four hundred billion, three hundred fourteen million, thirteen thousand, two hundred three".

Divisors: 1 19 97 113 1843 2147 10961 208259 554119217 10528265123 53749564049 62615471521 1021241716931 1189693958899 6073700737537 115400314013203