115403410021 has 4 divisors (see below), whose sum is σ = 115409269152. Its totient is φ = 115397550892.

The previous prime is 115403409929. The next prime is 115403410139. The reversal of 115403410021 is 120014304511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 120014304511 = 262147 ⋅457813.

It is a cyclic number.

It is not a de Polignac number, because 115403410021 - 2⁷ = 115403409893 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115403409974 and 115403410001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115403110021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2899921 + ... + 2939446.

It is an arithmetic number, because the mean of its divisors is an integer number (28852317288).

Almost surely, 2^115403410021 is an apocalyptic number.

It is an amenable number.

115403410021 is a deficient number, since it is larger than the sum of its proper divisors (5859131).

115403410021 is an equidigital number, since it uses as much as digits as its factorization.

115403410021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5859130.

The product of its (nonzero) digits is 480, while the sum is 22.

Adding to 115403410021 its reverse (120014304511), we get a palindrome (235417714532).

The spelling of 115403410021 in words is "one hundred fifteen billion, four hundred three million, four hundred ten thousand, twenty-one".