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11540402430153 = 319457787562931
BaseRepresentation
bin1010011111101111010110…
…0101100110000011001001
31111212020210111011111102220
42213323311211212003021
53003034221010231103
640313330535044253
72300523634066362
oct247736545460311
944766714144386
1011540402430153
11374a291350153
121364735510689
13659341b06b1c
142bc7b65a0b69
151502d42b7c53
hexa7ef59660c9

11540402430153 has 32 divisors (see below), whose sum is σ = 16253152842240. Its totient is φ = 7263472279680.

The previous prime is 11540402430119. The next prime is 11540402430203. The reversal of 11540402430153 is 35103420404511.

It is not a de Polignac number, because 11540402430153 - 212 = 11540402426057 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11540402430103) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20219098 + ... + 20782028.

It is an arithmetic number, because the mean of its divisors is an integer number (507911026320).

Almost surely, 211540402430153 is an apocalyptic number.

It is an amenable number.

11540402430153 is a deficient number, since it is larger than the sum of its proper divisors (4712750412087).

11540402430153 is a wasteful number, since it uses less digits than its factorization.

11540402430153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 564197.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 11540402430153 its reverse (35103420404511), we get a palindrome (46643822834664).

The spelling of 11540402430153 in words is "eleven trillion, five hundred forty billion, four hundred two million, four hundred thirty thousand, one hundred fifty-three".

Divisors: 1 3 19 57 457 787 1371 2361 8683 14953 26049 44859 359659 562931 1078977 1688793 6833521 10695689 20500563 32087067 257259467 443026697 771778401 1329080091 4887929873 8417507243 14663789619 25252521729 202463200529 607389601587 3846800810051 11540402430153