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115404053011 = 1323491956631
BaseRepresentation
bin110101101111010011…
…1100001101000010011
3102000212201002022110121
41223132213201220103
53342321414144021
6125003233211111
711223551160022
oct1533647415023
9360781068417
10115404053011
1144a40641125
121a448700a97
13ab61c88b00
14582abc28b9
153006763741
hex1ade9e1a13

115404053011 has 12 divisors (see below), whose sum is σ = 125322279600. Its totient is φ = 106221529440.

The previous prime is 115404052999. The next prime is 115404053021. The reversal of 115404053011 is 110350404511.

It is not a de Polignac number, because 115404053011 - 29 = 115404052499 is a prime.

It is a super-2 number, since 2×1154040530112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115404053021) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 919335 + ... + 1037296.

It is an arithmetic number, because the mean of its divisors is an integer number (10443523300).

Almost surely, 2115404053011 is an apocalyptic number.

115404053011 is a deficient number, since it is larger than the sum of its proper divisors (9918226589).

115404053011 is a wasteful number, since it uses less digits than its factorization.

115404053011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1957006 (or 1956993 counting only the distinct ones).

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 115404053011 its reverse (110350404511), we get a palindrome (225754457522).

The spelling of 115404053011 in words is "one hundred fifteen billion, four hundred four million, fifty-three thousand, eleven".

Divisors: 1 13 169 349 4537 58981 1956631 25436203 330670639 682864219 8877234847 115404053011