Base | Representation |
---|---|
bin | 110101101111011000… |
… | …0100011100100011101 |
3 | 102000212212112120201020 |
4 | 1223132300203210131 |
5 | 3342323020422003 |
6 | 125003400034353 |
7 | 11223610246425 |
oct | 1533660434435 |
9 | 360785476636 |
10 | 115406420253 |
11 | 44a41a08723 |
12 | 1a4494629b9 |
13 | ab62607447 |
14 | 582b23b485 |
15 | 3006a7ed53 |
hex | 1adec2391d |
115406420253 has 4 divisors (see below), whose sum is σ = 153875227008. Its totient is φ = 76937613500.
The previous prime is 115406420251. The next prime is 115406420263. The reversal of 115406420253 is 352024604511.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 115406420253 - 21 = 115406420251 is a prime.
It is a super-2 number, since 2×1154064202532 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115406420251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19234403373 + ... + 19234403378.
It is an arithmetic number, because the mean of its divisors is an integer number (38468806752).
Almost surely, 2115406420253 is an apocalyptic number.
It is an amenable number.
115406420253 is a deficient number, since it is larger than the sum of its proper divisors (38468806755).
115406420253 is an equidigital number, since it uses as much as digits as its factorization.
115406420253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38468806754.
The product of its (nonzero) digits is 28800, while the sum is 33.
The spelling of 115406420253 in words is "one hundred fifteen billion, four hundred six million, four hundred twenty thousand, two hundred fifty-three".
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