Base | Representation |
---|---|
bin | 10000110010110110100… |
… | …100011100101100000011 |
3 | 11002022222012120011012020 |
4 | 100302312210130230003 |
5 | 122402111221241311 |
6 | 2242105345332523 |
7 | 146245012130550 |
oct | 20626644345403 |
9 | 4068865504166 |
10 | 1154114243331 |
11 | 405503447a45 |
12 | 167812637143 |
13 | 84aa90292ba |
14 | 3dc063a9a27 |
15 | 2004b635c06 |
hex | 10cb691cb03 |
1154114243331 has 16 divisors (see below), whose sum is σ = 1761310887168. Its totient is φ = 658496124000.
The previous prime is 1154114243327. The next prime is 1154114243341. The reversal of 1154114243331 is 1333424114511.
It is a happy number.
It is not a de Polignac number, because 1154114243331 - 22 = 1154114243327 is a prime.
It is a super-2 number, since 2×11541142433312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1154114243292 and 1154114243301.
It is not an unprimeable number, because it can be changed into a prime (1154114243311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41557845 + ... + 41585606.
It is an arithmetic number, because the mean of its divisors is an integer number (110081930448).
Almost surely, 21154114243331 is an apocalyptic number.
1154114243331 is a deficient number, since it is larger than the sum of its proper divisors (607196643837).
1154114243331 is an equidigital number, since it uses as much as digits as its factorization.
1154114243331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83144122.
The product of its digits is 17280, while the sum is 33.
Adding to 1154114243331 its reverse (1333424114511), we get a palindrome (2487538357842).
The spelling of 1154114243331 in words is "one trillion, one hundred fifty-four billion, one hundred fourteen million, two hundred forty-three thousand, three hundred thirty-one".
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