1154130100531 has 4 divisors (see below), whose sum is σ = 1154508631000. Its totient is φ = 1153751570064.

The previous prime is 1154130100499. The next prime is 1154130100553. The reversal of 1154130100531 is 1350010314511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1154130100531 - 2⁵ = 1154130100499 is a prime.

It is a super-2 number, since 2×1154130100531² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1154130100496 and 1154130100505.

It is not an unprimeable number, because it can be changed into a prime (1154130100561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189260661 + ... + 189266758.

It is an arithmetic number, because the mean of its divisors is an integer number (288627157750).

Almost surely, 2^{1154130100531} is an apocalyptic number.

1154130100531 is a deficient number, since it is larger than the sum of its proper divisors (378530469).

1154130100531 is an equidigital number, since it uses as much as digits as its factorization.

1154130100531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 378530468.

The product of its (nonzero) digits is 900, while the sum is 25.

The spelling of 1154130100531 in words is "one trillion, one hundred fifty-four billion, one hundred thirty million, one hundred thousand, five hundred thirty-one".