Base | Representation |
---|---|
bin | 110101110000000111… |
… | …0110110110011000111 |
3 | 102000221121001111120211 |
4 | 1223200032312303013 |
5 | 3342400332444201 |
6 | 125010041540251 |
7 | 11224330335316 |
oct | 1534016666307 |
9 | 360847044524 |
10 | 115431140551 |
11 | 44a54962421 |
12 | 1a4557a4687 |
13 | ab6778123c |
14 | 583063427d |
15 | 3008d14651 |
hex | 1ae03b6cc7 |
115431140551 has 4 divisors (see below), whose sum is σ = 115552265472. Its totient is φ = 115310015632.
The previous prime is 115431140521. The next prime is 115431140567. The reversal of 115431140551 is 155041134511.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155041134511 = 9041 ⋅17148671.
It is a cyclic number.
It is not a de Polignac number, because 115431140551 - 219 = 115430616263 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115431140521) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60561031 + ... + 60562936.
It is an arithmetic number, because the mean of its divisors is an integer number (28888066368).
Almost surely, 2115431140551 is an apocalyptic number.
115431140551 is a deficient number, since it is larger than the sum of its proper divisors (121124921).
115431140551 is an equidigital number, since it uses as much as digits as its factorization.
115431140551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121124920.
The product of its (nonzero) digits is 6000, while the sum is 31.
The spelling of 115431140551 in words is "one hundred fifteen billion, four hundred thirty-one million, one hundred forty thousand, five hundred fifty-one".
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