1154314313131 has 4 divisors (see below), whose sum is σ = 1319216357872. Its totient is φ = 989412268392.

The previous prime is 1154314313071. The next prime is 1154314313147. The reversal of 1154314313131 is 1313134134511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1154314313131 - 2²⁵ = 1154280758699 is a prime.

It is a super-2 number, since 2×1154314313131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1154314313093 and 1154314313102.

It is not an unprimeable number, because it can be changed into a prime (1154314311131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82451022360 + ... + 82451022373.

It is an arithmetic number, because the mean of its divisors is an integer number (329804089468).

Almost surely, 2^{1154314313131} is an apocalyptic number.

1154314313131 is a deficient number, since it is larger than the sum of its proper divisors (164902044741).

1154314313131 is an equidigital number, since it uses as much as digits as its factorization.

1154314313131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164902044740.

The product of its digits is 6480, while the sum is 31.

Adding to 1154314313131 its reverse (1313134134511), we get a palindrome (2467448447642).

The spelling of 1154314313131 in words is "one trillion, one hundred fifty-four billion, three hundred fourteen million, three hundred thirteen thousand, one hundred thirty-one".