Base | Representation |
---|---|
bin | 10000110011000010110… |
… | …110100101011000010001 |
3 | 11002100111120100010212210 |
4 | 100303002312211120101 |
5 | 122403022000332423 |
6 | 2242142030342333 |
7 | 146253063602265 |
oct | 20630266453021 |
9 | 4070446303783 |
10 | 1154320324113 |
11 | 4055a9803540 |
12 | 16786b65a9a9 |
13 | 84b0c9322a8 |
14 | 3dc258d20a5 |
15 | 2005e791b93 |
hex | 10cc2da5611 |
1154320324113 has 8 divisors (see below), whose sum is σ = 1679011380576. Its totient is φ = 699588075200.
The previous prime is 1154320324063. The next prime is 1154320324139. The reversal of 1154320324113 is 3114230234511.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1154320324113 - 213 = 1154320315921 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1154320324193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17489701848 + ... + 17489701913.
It is an arithmetic number, because the mean of its divisors is an integer number (209876422572).
Almost surely, 21154320324113 is an apocalyptic number.
It is an amenable number.
1154320324113 is a deficient number, since it is larger than the sum of its proper divisors (524691056463).
1154320324113 is a wasteful number, since it uses less digits than its factorization.
1154320324113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34979403775.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 1154320324113 its reverse (3114230234511), we get a palindrome (4268550558624).
The spelling of 1154320324113 in words is "one trillion, one hundred fifty-four billion, three hundred twenty million, three hundred twenty-four thousand, one hundred thirteen".
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