115433103 has 4 divisors (see below), whose sum is σ = 153910808. Its totient is φ = 76955400.

The previous prime is 115433069. The next prime is 115433117. The reversal of 115433103 is 301334511.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-115433103 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 115433103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115433183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19238848 + ... + 19238853.

It is an arithmetic number, because the mean of its divisors is an integer number (38477702).

Almost surely, 2^115433103 is an apocalyptic number.

115433103 is a deficient number, since it is larger than the sum of its proper divisors (38477705).

115433103 is an equidigital number, since it uses as much as digits as its factorization.

115433103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38477704.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 115433103 is about 10743.9798491993. The cubic root of 115433103 is about 486.9041282408.

Adding to 115433103 its reverse (301334511), we get a palindrome (416767614).

The spelling of 115433103 in words is "one hundred fifteen million, four hundred thirty-three thousand, one hundred three".