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11543430250000 = 2456113113307
BaseRepresentation
bin1010011111111010101000…
…0011110011111000010000
31111212112121111112200102201
42213332222003303320100
53003111421121000000
640314551215452544
72300661651120445
oct247765203637020
944775544480381
1011543430250000
1137505a5492000
12136523b527154
136597051abbbc
142bc9c27699cc
1515041000496a
hexa7faa0f3e10

11543430250000 has 560 divisors, whose sum is σ = 31123097869248. Its totient is φ = 4146912000000.

The previous prime is 11543430249983. The next prime is 11543430250063. The reversal of 11543430250000 is 5203434511.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 37600749847 + ... + 37600750153.

Almost surely, 211543430250000 is an apocalyptic number.

11543430250000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11543430250000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15561548934624).

11543430250000 is an abundant number, since it is smaller than the sum of its proper divisors (19579667619248).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11543430250000 is an frugal number, since it uses more digits than its factorization.

11543430250000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 491 (or 438 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 11543430250000 its reverse (5203434511), we get a palindrome (11548633684511).

The spelling of 11543430250000 in words is "eleven trillion, five hundred forty-three billion, four hundred thirty million, two hundred fifty thousand".