1154393793793 has 4 divisors (see below), whose sum is σ = 1156744901808. Its totient is φ = 1152042685780.

The previous prime is 1154393793779. The next prime is 1154393793809. The reversal of 1154393793793 is 3973973934511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1154393793793 is a prime.

It is a super-2 number, since 2×1154393793793² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1154393793493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1175553271 + ... + 1175554252.

It is an arithmetic number, because the mean of its divisors is an integer number (289186225452).

Almost surely, 2^{1154393793793} is an apocalyptic number.

It is an amenable number.

1154393793793 is a deficient number, since it is larger than the sum of its proper divisors (2351108015).

1154393793793 is an equidigital number, since it uses as much as digits as its factorization.

1154393793793 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2351108014.

The product of its digits is 57868020, while the sum is 64.

The spelling of 1154393793793 in words is "one trillion, one hundred fifty-four billion, three hundred ninety-three million, seven hundred ninety-three thousand, seven hundred ninety-three".