115440541231 has 4 divisors (see below), whose sum is σ = 115441243632. Its totient is φ = 115439838832.

The previous prime is 115440541189. The next prime is 115440541253. The reversal of 115440541231 is 132145044511.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 115440541231 - 2³¹ = 113293057583 is a prime.

It is a super-2 number, since 2×115440541231² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115440541193 and 115440541202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115440548231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42270 + ... + 482356.

It is an arithmetic number, because the mean of its divisors is an integer number (28860310908).

Almost surely, 2^115440541231 is an apocalyptic number.

115440541231 is a deficient number, since it is larger than the sum of its proper divisors (702401).

115440541231 is an equidigital number, since it uses as much as digits as its factorization.

115440541231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 702400.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 115440541231 its reverse (132145044511), we get a palindrome (247585585742).

The spelling of 115440541231 in words is "one hundred fifteen billion, four hundred forty million, five hundred forty-one thousand, two hundred thirty-one".