11544214003 has 8 divisors (see below), whose sum is σ = 13194037760. Its totient is φ = 9894552840.

The previous prime is 11544213991. The next prime is 11544214007. The reversal of 11544214003 is 30041244511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11544214003 - 2³³ = 2954279411 is a prime.

It is a super-3 number, since 3×11544214003³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11544214007) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 251548 + ... + 293878.

It is an arithmetic number, because the mean of its divisors is an integer number (1649254720).

Almost surely, 2^11544214003 is an apocalyptic number.

11544214003 is a deficient number, since it is larger than the sum of its proper divisors (1649823757).

11544214003 is an equidigital number, since it uses as much as digits as its factorization.

11544214003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81297.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 11544214003 its reverse (30041244511), we get a palindrome (41585458514).

The spelling of 11544214003 in words is "eleven billion, five hundred forty-four million, two hundred fourteen thousand, three".