11544313251201 has 4 divisors (see below), whose sum is σ = 15392417668272. Its totient is φ = 7696208834132.

The previous prime is 11544313251193. The next prime is 11544313251227. The reversal of 11544313251201 is 10215231344511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11544313251201 - 2³ = 11544313251193 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11544313251271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1924052208531 + ... + 1924052208536.

It is an arithmetic number, because the mean of its divisors is an integer number (3848104417068).

Almost surely, 2^{11544313251201} is an apocalyptic number.

It is an amenable number.

11544313251201 is a deficient number, since it is larger than the sum of its proper divisors (3848104417071).

11544313251201 is an equidigital number, since it uses as much as digits as its factorization.

11544313251201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3848104417070.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 11544313251201 its reverse (10215231344511), we get a palindrome (21759544595712).

The spelling of 11544313251201 in words is "eleven trillion, five hundred forty-four billion, three hundred thirteen million, two hundred fifty-one thousand, two hundred one".