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11544313251193 is a prime number
BaseRepresentation
bin1010011111111101111010…
…1100001100010101111001
31111212121220001001210100121
42213333132230030111321
53003120223143014233
640315215001333241
72301022562400112
oct247773654142571
944777801053317
1011544313251193
113750a08963958
121365447197221
13659816103208
142bca67b3d209
151504627c492d
hexa7fdeb0c579

11544313251193 has 2 divisors, whose sum is σ = 11544313251194. Its totient is φ = 11544313251192.

The previous prime is 11544313251167. The next prime is 11544313251227. The reversal of 11544313251193 is 39115231344511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7899848984889 + 3644464266304 = 2810667^2 + 1909048^2 .

It is a cyclic number.

It is not a de Polignac number, because 11544313251193 - 221 = 11544311154041 is a prime.

It is not a weakly prime, because it can be changed into another prime (11544313261193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5772156625596 + 5772156625597.

It is an arithmetic number, because the mean of its divisors is an integer number (5772156625597).

Almost surely, 211544313251193 is an apocalyptic number.

It is an amenable number.

11544313251193 is a deficient number, since it is larger than the sum of its proper divisors (1).

11544313251193 is an equidigital number, since it uses as much as digits as its factorization.

11544313251193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 194400, while the sum is 43.

The spelling of 11544313251193 in words is "eleven trillion, five hundred forty-four billion, three hundred thirteen million, two hundred fifty-one thousand, one hundred ninety-three".