115450433203041 has 64 divisors (see below), whose sum is σ = 174431287699200. Its totient is φ = 76397193792000.

The previous prime is 115450433202959. The next prime is 115450433203051. The reversal of 115450433203041 is 140302334054511.

115450433203041 is a `hidden beast` number, since 1 + 1 + 54 + 504 + 3 + 32 + 0 + 30 + 41 = 666.

It is not a de Polignac number, because 115450433203041 - 2⁹ = 115450433202529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115450433202987 and 115450433203005.

It is not an unprimeable number, because it can be changed into a prime (115450433203051) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4760634166 + ... + 4760658416.

It is an arithmetic number, because the mean of its divisors is an integer number (2725488870300).

Almost surely, 2^{115450433203041} is an apocalyptic number.

It is an amenable number.

115450433203041 is a deficient number, since it is larger than the sum of its proper divisors (58980854496159).

115450433203041 is an equidigital number, since it uses as much as digits as its factorization.

115450433203041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40298 (or 40280 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 36.

Adding to 115450433203041 its reverse (140302334054511), we get a palindrome (255752767257552).

The spelling of 115450433203041 in words is "one hundred fifteen trillion, four hundred fifty billion, four hundred thirty-three million, two hundred three thousand, forty-one".