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11552000504015 = 52310400100803
BaseRepresentation
bin1010100000011010100011…
…1000101111000011001111
31111220100201202222200210002
42220012220320233003033
53003231444112112030
640322525450034515
72301414225066656
oct250065070570317
944810652880702
1011552000504015
1137541a3140764
121366a31718a3b
1365a46c90441a
142bd196a7619d
151507625e4245
hexa81a8e2f0cf

11552000504015 has 4 divisors (see below), whose sum is σ = 13862400604824. Its totient is φ = 9241600403208.

The previous prime is 11552000503943. The next prime is 11552000504029. The reversal of 11552000504015 is 51040500025511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11552000504015 is a prime.

It is a super-3 number, since 3×115520005040153 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1155200050397 + ... + 1155200050406.

It is an arithmetic number, because the mean of its divisors is an integer number (3465600151206).

Almost surely, 211552000504015 is an apocalyptic number.

11552000504015 is a deficient number, since it is larger than the sum of its proper divisors (2310400100809).

11552000504015 is an equidigital number, since it uses as much as digits as its factorization.

11552000504015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2310400100808.

The product of its (nonzero) digits is 5000, while the sum is 29.

Adding to 11552000504015 its reverse (51040500025511), we get a palindrome (62592500529526).

The spelling of 11552000504015 in words is "eleven trillion, five hundred fifty-two billion, five hundred four thousand, fifteen".

Divisors: 1 5 2310400100803 11552000504015