Base | Representation |
---|---|
bin | 1010100000011010100011… |
… | …1000111001000101101011 |
3 | 1111220100201210001210011220 |
4 | 2220012220320321011223 |
5 | 3003231444114421011 |
6 | 40322525450553123 |
7 | 2301414225330564 |
oct | 250065070710553 |
9 | 44810653053156 |
10 | 11552000545131 |
11 | 37541a3169642 |
12 | 1366a317387a3 |
13 | 65a46c91a057 |
14 | 2bd196a8716b |
15 | 150762601506 |
hex | a81a8e3916b |
11552000545131 has 16 divisors (see below), whose sum is σ = 15668134041600. Its totient is φ = 7568673781088.
The previous prime is 11552000545087. The next prime is 11552000545139. The reversal of 11552000545131 is 13154500025511.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 11552000545131 - 213 = 11552000536939 is a prime.
It is a super-2 number, since 2×115520005451312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11552000545092 and 11552000545101.
It is not an unprimeable number, because it can be changed into a prime (11552000545139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8544651 + ... + 9803828.
It is an arithmetic number, because the mean of its divisors is an integer number (979258377600).
Almost surely, 211552000545131 is an apocalyptic number.
11552000545131 is a deficient number, since it is larger than the sum of its proper divisors (4116133496469).
11552000545131 is a wasteful number, since it uses less digits than its factorization.
11552000545131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18352098.
The product of its (nonzero) digits is 15000, while the sum is 33.
The spelling of 11552000545131 in words is "eleven trillion, five hundred fifty-two billion, five hundred forty-five thousand, one hundred thirty-one".
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