Base | Representation |
---|---|
bin | 10101100001010000… |
… | …01101000110010001 |
3 | 1002211011111121210022 |
4 | 22300220031012101 |
5 | 142130113422032 |
6 | 5150230313225 |
7 | 556205060321 |
oct | 126050150621 |
9 | 32734447708 |
10 | 11553264017 |
11 | 4999575289 |
12 | 22a51b8815 |
13 | 112173b6c9 |
14 | 7b856d281 |
15 | 479429512 |
hex | 2b0a0d191 |
11553264017 has 4 divisors (see below), whose sum is σ = 11553537600. Its totient is φ = 11552990436.
The previous prime is 11553264011. The next prime is 11553264061. The reversal of 11553264017 is 71046235511.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11553264017 - 214 = 11553247633 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11553264011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58517 + ... + 162882.
It is an arithmetic number, because the mean of its divisors is an integer number (2888384400).
Almost surely, 211553264017 is an apocalyptic number.
It is an amenable number.
11553264017 is a deficient number, since it is larger than the sum of its proper divisors (273583).
11553264017 is an equidigital number, since it uses as much as digits as its factorization.
11553264017 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 273582.
The product of its (nonzero) digits is 25200, while the sum is 35.
Adding to 11553264017 its reverse (71046235511), we get a palindrome (82599499528).
The spelling of 11553264017 in words is "eleven billion, five hundred fifty-three million, two hundred sixty-four thousand, seventeen".
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