Base | Representation |
---|---|
bin | 10000110100000100100… |
… | …101000111011010000001 |
3 | 11002110100102021222021122 |
4 | 100310010211013122001 |
5 | 122412301244304103 |
6 | 2242443301402025 |
7 | 146322313542623 |
oct | 20640445073201 |
9 | 4073312258248 |
10 | 1155423041153 |
11 | 406015204137 |
12 | 167b18a09315 |
13 | 84c57224894 |
14 | 3dccc13ac13 |
15 | 200c64b2b38 |
hex | 10d04947681 |
1155423041153 has 4 divisors (see below), whose sum is σ = 1166221387440. Its totient is φ = 1144624694868.
The previous prime is 1155423041137. The next prime is 1155423041203. The reversal of 1155423041153 is 3511403245511.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1155423041153 - 24 = 1155423041137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1155423041753) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5399172983 + ... + 5399173196.
It is an arithmetic number, because the mean of its divisors is an integer number (291555346860).
Almost surely, 21155423041153 is an apocalyptic number.
It is an amenable number.
1155423041153 is a deficient number, since it is larger than the sum of its proper divisors (10798346287).
1155423041153 is a wasteful number, since it uses less digits than its factorization.
1155423041153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10798346286.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 1155423041153 its reverse (3511403245511), we get a palindrome (4666826286664).
The spelling of 1155423041153 in words is "one trillion, one hundred fifty-five billion, four hundred twenty-three million, forty-one thousand, one hundred fifty-three".
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