11555015001001 has 4 divisors (see below), whose sum is σ = 11581098556752. Its totient is φ = 11528931445252.

The previous prime is 11555015000983. The next prime is 11555015001037. The reversal of 11555015001001 is 10010051055511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11555015001001 - 2¹⁹ = 11555014476713 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11555015101001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13041777211 + ... + 13041778096.

It is an arithmetic number, because the mean of its divisors is an integer number (2895274639188).

Almost surely, 2^{11555015001001} is an apocalyptic number.

It is an amenable number.

11555015001001 is a deficient number, since it is larger than the sum of its proper divisors (26083555751).

11555015001001 is an equidigital number, since it uses as much as digits as its factorization.

11555015001001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26083555750.

The product of its (nonzero) digits is 625, while the sum is 25.

Adding to 11555015001001 its reverse (10010051055511), we get a palindrome (21565066056512).

The spelling of 11555015001001 in words is "eleven trillion, five hundred fifty-five billion, fifteen million, one thousand, one".