115551342200241 has 24 divisors (see below), whose sum is σ = 167051332123104. Its totient is φ = 76967864850240.

The previous prime is 115551342200233. The next prime is 115551342200243. The reversal of 115551342200241 is 142002243155511.

115551342200241 is a `hidden beast` number, since 1 + 1 + 5 + 5 + 51 + 342 + 20 + 0 + 241 = 666.

It is not a de Polignac number, because 115551342200241 - 2³ = 115551342200233 is a prime.

It is a super-2 number, since 2×115551342200241² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115551342200196 and 115551342200205.

It is not an unprimeable number, because it can be changed into a prime (115551342200243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 58434106 + ... + 60379196.

It is an arithmetic number, because the mean of its divisors is an integer number (6960472171796).

Almost surely, 2^{115551342200241} is an apocalyptic number.

It is an amenable number.

115551342200241 is a deficient number, since it is larger than the sum of its proper divisors (51499989922863).

115551342200241 is a wasteful number, since it uses less digits than its factorization.

115551342200241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1950781 (or 1950778 counting only the distinct ones).

The product of its (nonzero) digits is 48000, while the sum is 36.

Adding to 115551342200241 its reverse (142002243155511), we get a palindrome (257553585355752).

The spelling of 115551342200241 in words is "one hundred fifteen trillion, five hundred fifty-one billion, three hundred forty-two million, two hundred thousand, two hundred forty-one".