Base | Representation |
---|---|
bin | 1010100000100111010101… |
… | …0100110101001010001100 |
3 | 1111220200120210222112112101 |
4 | 2220021311110311022030 |
5 | 3003311010141434012 |
6 | 40324254053044444 |
7 | 2301565223646223 |
oct | 250116524651214 |
9 | 44820523875471 |
10 | 11555430421132 |
11 | 37556a3250204 |
12 | 136762a326724 |
13 | 65a8983a3590 |
14 | 2bd4003cdcba |
15 | 1508b37aad57 |
hex | a827553528c |
11555430421132 has 12 divisors (see below), whose sum is σ = 21777541947616. Its totient is φ = 5333275578960.
The previous prime is 11555430421069. The next prime is 11555430421193. The reversal of 11555430421132 is 23112403455511.
It is a super-2 number, since 2×115554304211322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11555430421091 and 11555430421100.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111109907844 + ... + 111109907947.
Almost surely, 211555430421132 is an apocalyptic number.
It is an amenable number.
11555430421132 is a deficient number, since it is larger than the sum of its proper divisors (10222111526484).
11555430421132 is a wasteful number, since it uses less digits than its factorization.
11555430421132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 222219815808 (or 222219815806 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 11555430421132 its reverse (23112403455511), we get a palindrome (34667833876643).
The spelling of 11555430421132 in words is "eleven trillion, five hundred fifty-five billion, four hundred thirty million, four hundred twenty-one thousand, one hundred thirty-two".
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