11560143631141 has 8 divisors (see below), whose sum is σ = 13211778063104. Its totient is φ = 9908555534640.

The previous prime is 11560143631133. The next prime is 11560143631159. The reversal of 11560143631141 is 14113634106511.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11560143631141 - 2³ = 11560143631133 is a prime.

It is a super-3 number, since 3×11560143631141³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11560143631141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11560143631171) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11047590 + ... + 12048631.

It is an arithmetic number, because the mean of its divisors is an integer number (1651472257888).

Almost surely, 2^{11560143631141} is an apocalyptic number.

It is an amenable number.

11560143631141 is a deficient number, since it is larger than the sum of its proper divisors (1651634431963).

11560143631141 is an equidigital number, since it uses as much as digits as its factorization.

11560143631141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23167731.

The product of its (nonzero) digits is 25920, while the sum is 37.

Adding to 11560143631141 its reverse (14113634106511), we get a palindrome (25673777737652).

The spelling of 11560143631141 in words is "eleven trillion, five hundred sixty billion, one hundred forty-three million, six hundred thirty-one thousand, one hundred forty-one".