Base | Representation |
---|---|
bin | 110101110101110100… |
… | …0101100011001000111 |
3 | 102001102221001200201012 |
4 | 1223223220230121013 |
5 | 3343243322304142 |
6 | 125041034352435 |
7 | 11232142502000 |
oct | 1535350543107 |
9 | 361387050635 |
10 | 115622463047 |
11 | 45042958893 |
12 | 1a4a988b71b |
13 | ab982ba910 |
14 | 584bbd81a7 |
15 | 301aa07882 |
hex | 1aeba2c647 |
115622463047 has 16 divisors (see below), whose sum is σ = 145208750400. Its totient is φ = 91481505696.
The previous prime is 115622463041. The next prime is 115622463049. The reversal of 115622463047 is 740364226511.
It is not a de Polignac number, because 115622463047 - 214 = 115622446663 is a prime.
It is a super-2 number, since 2×1156224630472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 115622462995 and 115622463013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115622463041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12960608 + ... + 12969525.
It is an arithmetic number, because the mean of its divisors is an integer number (9075546900).
Almost surely, 2115622463047 is an apocalyptic number.
115622463047 is a deficient number, since it is larger than the sum of its proper divisors (29586287353).
115622463047 is an equidigital number, since it uses as much as digits as its factorization.
115622463047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25930167 (or 25930153 counting only the distinct ones).
The product of its (nonzero) digits is 241920, while the sum is 41.
Adding to 115622463047 its reverse (740364226511), we get a palindrome (855986689558).
The spelling of 115622463047 in words is "one hundred fifteen billion, six hundred twenty-two million, four hundred sixty-three thousand, forty-seven".
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