1156444062421 has 4 divisors (see below), whose sum is σ = 1206724239072. Its totient is φ = 1106163885772.

The previous prime is 1156444062413. The next prime is 1156444062443. The reversal of 1156444062421 is 1242604446511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1156444062421 - 2³ = 1156444062413 is a prime.

It is a super-3 number, since 3×1156444062421³ (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1156444062481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25140088291 + ... + 25140088336.

It is an arithmetic number, because the mean of its divisors is an integer number (301681059768).

Almost surely, 2^{1156444062421} is an apocalyptic number.

It is an amenable number.

1156444062421 is a deficient number, since it is larger than the sum of its proper divisors (50280176651).

1156444062421 is an equidigital number, since it uses as much as digits as its factorization.

1156444062421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50280176650.

The product of its (nonzero) digits is 184320, while the sum is 40.

The spelling of 1156444062421 in words is "one trillion, one hundred fifty-six billion, four hundred forty-four million, sixty-two thousand, four hundred twenty-one".