Base | Representation |
---|---|
bin | 1010100011111110101000… |
… | …1111001110010100010001 |
3 | 1112010012202201102112120120 |
4 | 2220333222033032110101 |
5 | 3010232341433213213 |
6 | 40411013110500453 |
7 | 2306012402120433 |
oct | 250775217162421 |
9 | 45105681375516 |
10 | 11613226460433 |
11 | 3778161642a44 |
12 | 137687a064729 |
13 | 6631793433c0 |
14 | 2c2124294653 |
15 | 1521477ad423 |
hex | a8fea3ce511 |
11613226460433 has 32 divisors (see below), whose sum is σ = 17006627568000. Its totient is φ = 7005341293056.
The previous prime is 11613226460357. The next prime is 11613226460449. The reversal of 11613226460433 is 33406462231611.
It is not a de Polignac number, because 11613226460433 - 213 = 11613226452241 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11613226460333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6427660 + ... + 8033757.
It is an arithmetic number, because the mean of its divisors is an integer number (531457111500).
Almost surely, 211613226460433 is an apocalyptic number.
11613226460433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11613226460433 is a deficient number, since it is larger than the sum of its proper divisors (5393401107567).
11613226460433 is a wasteful number, since it uses less digits than its factorization.
11613226460433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14461841.
The product of its (nonzero) digits is 373248, while the sum is 42.
The spelling of 11613226460433 in words is "eleven trillion, six hundred thirteen billion, two hundred twenty-six million, four hundred sixty thousand, four hundred thirty-three".
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