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11614212173 = 107108544039
BaseRepresentation
bin10101101000100001…
…01101000001001101
31002222102012002221102
422310100231001031
5142241214242143
65200244512445
7560545113614
oct126420550115
932872162842
1011614212173
114a1aa13563
1223016ab725
13113125b0c5
147c26b687b
1547e9680b8
hex2b442d04d

11614212173 has 4 divisors (see below), whose sum is σ = 11722756320. Its totient is φ = 11505668028.

The previous prime is 11614212139. The next prime is 11614212191. The reversal of 11614212173 is 37121241611.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 37121241611 = 160877230743.

It is a cyclic number.

It is not a de Polignac number, because 11614212173 - 26 = 11614212109 is a prime.

It is a super-2 number, since 2×116142121732 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11614212073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54271913 + ... + 54272126.

It is an arithmetic number, because the mean of its divisors is an integer number (2930689080).

Almost surely, 211614212173 is an apocalyptic number.

It is an amenable number.

11614212173 is a deficient number, since it is larger than the sum of its proper divisors (108544147).

11614212173 is a wasteful number, since it uses less digits than its factorization.

11614212173 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 108544146.

The product of its digits is 2016, while the sum is 29.

Adding to 11614212173 its reverse (37121241611), we get a palindrome (48735453784).

The spelling of 11614212173 in words is "eleven billion, six hundred fourteen million, two hundred twelve thousand, one hundred seventy-three".

Divisors: 1 107 108544039 11614212173