Base | Representation |
---|---|
bin | 10101101000101111… |
… | …01100000110001011 |
3 | 1002222112122010220202 |
4 | 22310113230012023 |
5 | 142242201342103 |
6 | 5200352042415 |
7 | 560566511516 |
oct | 126427540613 |
9 | 32875563822 |
10 | 11616043403 |
11 | 4a20a54378 |
12 | 230223340b |
13 | 113174c783 |
14 | 7c2a31d7d |
15 | 47ebca988 |
hex | 2b45ec18b |
11616043403 has 4 divisors (see below), whose sum is σ = 11929990560. Its totient is φ = 11302096248.
The previous prime is 11616043393. The next prime is 11616043451. The reversal of 11616043403 is 30434061611.
11616043403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30434061611 = 131 ⋅232321081.
It is a cyclic number.
It is not a de Polignac number, because 11616043403 - 210 = 11616042379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11616043493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156973523 + ... + 156973596.
It is an arithmetic number, because the mean of its divisors is an integer number (2982497640).
Almost surely, 211616043403 is an apocalyptic number.
11616043403 is a deficient number, since it is larger than the sum of its proper divisors (313947157).
11616043403 is an equidigital number, since it uses as much as digits as its factorization.
11616043403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 313947156.
The product of its (nonzero) digits is 5184, while the sum is 29.
The spelling of 11616043403 in words is "eleven billion, six hundred sixteen million, forty-three thousand, four hundred three".
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