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116226130153 = 716603732879
BaseRepresentation
bin110110000111110011…
…1100000000011101001
3102002222222222011022011
41230033213200003221
53401012342131103
6125221001155521
711253122543260
oct1541747400351
9362888864264
10116226130153
1145322690921
121a637a8bba1
13ac6339b6a3
1458a80575d7
1530539ebd6d
hex1b0f9e00e9

116226130153 has 4 divisors (see below), whose sum is σ = 132829863040. Its totient is φ = 99622397268.

The previous prime is 116226130151. The next prime is 116226130177. The reversal of 116226130153 is 351031622611.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 116226130153 - 21 = 116226130151 is a prime.

It is not an unprimeable number, because it can be changed into a prime (116226130151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8301866433 + ... + 8301866446.

It is an arithmetic number, because the mean of its divisors is an integer number (33207465760).

Almost surely, 2116226130153 is an apocalyptic number.

It is an amenable number.

116226130153 is a deficient number, since it is larger than the sum of its proper divisors (16603732887).

116226130153 is an equidigital number, since it uses as much as digits as its factorization.

116226130153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16603732886.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 116226130153 its reverse (351031622611), we get a palindrome (467257752764).

The spelling of 116226130153 in words is "one hundred sixteen billion, two hundred twenty-six million, one hundred thirty thousand, one hundred fifty-three".

Divisors: 1 7 16603732879 116226130153