Base | Representation |
---|---|
bin | 1010100100101011000001… |
… | …1100010011011001111011 |
3 | 1112011100112010002001121221 |
4 | 2221022300130103121323 |
5 | 3010431242234300012 |
6 | 40420303312012511 |
7 | 2306613564104611 |
oct | 251126034233173 |
9 | 45140463061557 |
10 | 11625141712507 |
11 | 3782216480204 |
12 | 1379044531137 |
13 | 664327a7470b |
14 | 2c29349316b1 |
15 | 1525e388d507 |
hex | a92b071367b |
11625141712507 has 32 divisors (see below), whose sum is σ = 12144212720640. Its totient is φ = 11119628298240.
The previous prime is 11625141712451. The next prime is 11625141712517. The reversal of 11625141712507 is 70521714152611.
11625141712507 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 11625141712507 - 223 = 11625133323899 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (43).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11625141712517) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 759160483 + ... + 759175795.
It is an arithmetic number, because the mean of its divisors is an integer number (379506647520).
Almost surely, 211625141712507 is an apocalyptic number.
11625141712507 is a deficient number, since it is larger than the sum of its proper divisors (519071008133).
11625141712507 is a wasteful number, since it uses less digits than its factorization.
11625141712507 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17083.
The product of its (nonzero) digits is 117600, while the sum is 43.
The spelling of 11625141712507 in words is "eleven trillion, six hundred twenty-five billion, one hundred forty-one million, seven hundred twelve thousand, five hundred seven".
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